The sphere x2 y2 z2 = 4 is the same as ˆ= 2 The cone z = p 3(x2 y2) can be written as ˚= ˇ 6 (2) So, the volume is Z 2ˇ 0 Z ˇ=6 0 Z 2 0 1 ˆ2 sin˚dˆd˚d 5 Write an iterated integral which gives the volume of the solid enclosed by z2 = x2 y2, z= 1, and z= 2 (You need not evaluate) xTake the square root of both sides of the equation x^ {2}y^ {2}z^ {2}=0 Subtract z^ {2} from both sides y^ {2}x^ {2}z^ {2}=0 Quadratic equations like this one, with an x^ {2} term but no x term, can still be solved using the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a}, once they are put in standard form ax^ {2}bxc=0Then a shortened version of the integral is ∫∫ D1 ⋅ dS We have already seen
The Divergence Theorem Calculus Volume 3
